Russell797
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Lets start with the mean free path of a photon with a 400 ppm gas, I think it is only about 1 inch.
This would mean that no 15 um photon would ever make it to altitude.
In addition the energy level of that 15 um photon, is well below the vibration state of CO2,
all that is left are spin states that emit long wavelength IR and radio waves.
The 15 um radiation is present in the atmosphere simply because of the atmosphere’s temperature. The averaged global surface radiates most strongly at 10 um. To the right on the Planck curve is the 15 um band. CO2 in the first inch above the surface absorbs that 15 um, rather than allowing it to pass on out to space. Some thermal radiation does pass on directly to space. That portion of the spectrum is called the atmospheric window.
The first inch of atmosphere radiates in all direction thermally. The second inch of CO2 absorbs all the 15 um. This happens all the way up to about 16,000 feet where the optical thickness of CO2 is reduced such that more 15 um escapes to space than is retained within the atmospheric column.
At a temperature of about -50C most of the atmosphere is radiating thermally with a peak near 15 um. Most of the photons are 15 um at altitude where that temperature prevails..