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Reinventing college maths.

BrettNortje

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I have gotten bored of the one dimensional formulas of high school maths, and, wish to impress you further, so, i am moving onto college maths, fluid mechanics of navier stokes to be specific.



So, we have an ultra hard equation? this will be simplified by observing in english language how to do it, yes?

This would mean we take the velocity of the fluid - how fast it is going adds to how much force is in there - and the density of the pipe or such. this would mean that we take density of the pipe minus the velocity or pressure on it, of course.

To calculate the pressure, you take the volume plus velocity, yes? so;

[Density mass of pipe / Volume + velocity] = capacity.
 

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Then, there is differential equations. these are about physical values, changes in them and others and the relationship between them. so if we were to look at this;

5fe49befc15be8cc358653332fde7f46398699ef


We could see it sounds hard, yes? look at all that junk!

So, we need to simplify it. the best way to do that is to work with the value on the left, as, it is equal to the equation on the right, yes? this means we need only work out [Au / At], yes? without these values, we need to find the real values and work it out, which would be [a / a = 1] meaning everything is equal to one, so, it is one divided by one, equaling one, one [u * one] / [t * one] = [u / t].
 
When it comes to waves, which are a standard model, there is a lot of maths involved. this is why i am trying to make it easier for everyone to understand, as, it is very important in getting to 'friction' where things are moving. this is because the only activity needed to move was friction of some sort, and, even in 'dead mass' there is friction between the bonds keeping them together.

In electromagnetism, there are either four in total, but two pairs, of right angles where they push against each other - even though they are combined into the same 'force,' they polarize against each other and at the same time are attracted to the other type of proton or electron 'charge.' this means they 'spiral' as this is like a screw driver, with the 'whirl' jutting out as the proton and the inner line being pulled together with the whirl. this means it projects in various directions, but it doesn't change direction unless there is resistance or attraction to another wave - like a bond, yes?

The frequencies they speak about in this are rubbish - the type of wave it is is down to's charges independent of the charge of the, for example, light, which can gain radiation. this radiation comes from a different 'composition' of the ray, not 'intensity.' for example, radio active light is radio active because it has bonds of ions or baryons or something, not because it is more dense, although having a more dense radio active light, well, they could stack and become more intense, yes?

Due to resistance, due to density, wave packets move at different speeds to the rest of the guiding photons, which are the force carrying the wave. photons will deliver mass from one place to another, and, even though they have no weight, they would not exist unless burning fuel from the protons, as nothing may exist without mass, of course.

Now, let's get down to some maths?

d5049d1cccf073c4a7392525a305b5f9dd4eb614


This is where we need to analyze 'the momentum of water waves.' this would be down to [ a exponential * 2].
 
Then, there is differential equations. these are about physical values, changes in them and others and the relationship between them. so if we were to look at this;

5fe49befc15be8cc358653332fde7f46398699ef


We could see it sounds hard, yes? look at all that junk!

So, we need to simplify it. the best way to do that is to work with the value on the left, as, it is equal to the equation on the right, yes? this means we need only work out [Au / At], yes? without these values, we need to find the real values and work it out, which would be [a / a = 1] meaning everything is equal to one, so, it is one divided by one, equaling one, one [u * one] / [t * one] = [u / t].

In general, PDEs are no joke. The one you listed there would probably have to be solved by some sort of method of characteristics.

Or you could just solve it numerically. lol
 
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